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Math Help - Help if you please...

  1. #1
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    Help if you please...

    The manufacturer of Pars (chocolate) Bars is running a marketing promotion. As part of this promotion, 10% of Pars Bars wrappers display a token which entitles the purchaser to a free Pars Bar. Joe plans to buy 12 Pars Bars.
    What is
    (a) the probability distribution of the number of free Pars Bars that Joe can win?
    (b) the probability that Joe wins at least two free Pars Bars?
    (c) the most likely number of free Pars Bars Joe can win?

    regards.
    Last edited by omrkwlh; April 22nd 2007 at 05:50 AM. Reason: tittle
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by omrkwlh View Post
    The manufacturer of Pars (chocolate) Bars is running a marketing promotion. As part of this promotion, 10% of Pars Bars wrappers display a token which entitles the purchaser to a free Pars Bar. Joe plans to buy 12 Pars Bars.
    What is
    (a) the probability distribution of the number of free Pars Bars that Joe can win?
    (b) the probability that Joe wins at least two free Pars Bars?
    (c) the most likely number of free Pars Bars Joe can win?

    regards.
    a) Binomial B(12, 0.1)

    b) b(2; 12, 0.1) = 12!/[2! (12-2)!] 0.1^2 (1-0.1)^(12-2) ~= 0.23

    c) b(0, 12, 0.1) ~= 0.28, b(1, 12, 0.1) ~= 0.38, b(2, 12, 0.1) ~= 0.23
    and the probability decreases for larger numbers, so the most likley number
    of bars is 1.

    RonL
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