If f(x,y) = 4/3 , 0<x<1 , x^3<y<1 . How do i got about finding P(X>Y) ?
Im not sure between which x and y values to integrate... Thanks
Sketch the region in the x-y plane over which f(x,y) is non-zero, now mark that part of the region where x>y. By now the region over which you need to integrate will be obvious.