Originally Posted by
braddy HI please can someone cheeck this problem I tried to do?
Suppose X is the waiting time, in seconds, for a certain particle's emmission,
f(x)=0.1e^(-0.1x), x>0
0 elsewhere.
You are simualting a random sample of 2 values of X. You have simulated the following 2 values of Y, where Y has a (0,1) uniform pdf; y1=0.1942, y2=0.6209.
Find the 2 simulated values of X, x1 and x2.
Here what I did.
f(x)=0.1e^(-0.1x)
--> F(x)=1-e^(-0.1x)
let u =F(x)=1-e^(-0.1x)
x= -[ln(1-u)]/0.1 (1)
then for x1 take y1=0.1942=u , replace in the (1)
x1=2.1591
I do the same for x2. you get x2=9.6996
Is it the correct way to do it?
Thank you.