RV X and Y are identicaly independent distributed with distribution B(0.3,2)Originally Posted by braddy
Hence their joint distribution is the product of their individual distributions:
p(X=x, Y=y) = 2!/[(2-x)! x!] 0.3^x (1-0.3)^(2-x) 2!/[(2-y)! y!] 0.3^y (1-0.3)^(2-y)
x=0, 1 or 2 y=0, 1 or 2.
p(X>Y) = p(X=0, Y=1 or 2) + p(X=1, Y=2) = p(X=0,Y=1) + p(X=0,Y=2) + p(X=1,Y=2)
which can be evaluated from the joint distribution given above.
RonL