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Math Help - The Poisson Distribution?

  1. #1
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    The Poisson Distribution?

    Customer arrivals at a checkout counter have a Poisson distribution with an average of 7 per hour. For a given hour, find the probabilities of the following events:

    a) Exactly seven customers arrive
    b) No more than two customers arrive
    c) At least two customers arrive

    Can someone help me figure this out? I don't know how to approach this problem.
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  2. #2
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    These can be calculated directly.

    p(7) = \frac{e^{-7}\cdot 7^{7}}{7!}

    p(No more than 2) = p(0)+p(1)+p(2)

    p(at least 2) = 1- (p(0)+p(1))

    Let's see what you get.
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  3. #3
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    Quote Originally Posted by TKHunny View Post
    These can be calculated directly.

    p(7) = \frac{e^{-7}\cdot 7^{7}}{7!}

    p(No more than 2) = p(0)+p(1)+p(2)

    p(at least 2) = 1- (p(0)+p(1))

    Let's see what you get.
    Thanks for your help.
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