Let be normal distributed with mean and common variance . i = 1,...,a ; j = 1,...,b;k = 1,...,c Find the variance of where n = abc. Then I would multiply it by 'a' to find Have I made a mistake somewhere?
Last edited by statmajor; March 25th 2010 at 06:40 PM.
Follow Math Help Forum on Facebook and Google+
I n=bc instead, but I don't follow your comment on multiplying by a, which may then agree with my computation. Originally Posted by statmajor Let be normal distributed with mean and common variance . i = 1,...,a ; j = 1,...,b;k = 1,...,c Find the variance of where n = abc. Then I would multiply it by 'a' to find Have I made a mistake somewhere?
I calculated , and not , so I'll need to sum up from i= 1,...,a to get
Are the observations independent? If they are, then
View Tag Cloud