Let be normal distributed with mean and common variance . i = 1,...,a ; j = 1,...,b;k = 1,...,c Find the variance of where n = abc. Then I would multiply it by 'a' to find Have I made a mistake somewhere?
Last edited by statmajor; Mar 25th 2010 at 06:40 PM.
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I n=bc instead, but I don't follow your comment on multiplying by a, which may then agree with my computation. Originally Posted by statmajor Let be normal distributed with mean and common variance . i = 1,...,a ; j = 1,...,b;k = 1,...,c Find the variance of where n = abc. Then I would multiply it by 'a' to find Have I made a mistake somewhere?
I calculated , and not , so I'll need to sum up from i= 1,...,a to get
Are the observations independent? If they are, then
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