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Math Help - Geometrical distribution

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    Geometrical distribution

    g(x; p) = p(1 − p)^(x-1), x = 1, 2, . . .
    0, else

    How can I find an expression for the cumulative probability distribution for this variable? That is, F(x) = P(X (less or equal to x)

    Thanks!
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    Quote Originally Posted by gralla55 View Post
    g(x; p) = p(1 − p)^(x-1), x = 1, 2, . . .
    0, else
    How can I find an expression for the cumulative probability distribution for this variable? That is, F(x) = P(X (less or equal to x)
    Is this what you are asking \sum\limits_{x = 1}^n {p\left( {1 - p} \right)^{x - 1} }  = 1 - \left( {1 - p} \right)^n ~?
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