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Math Help - Proof

  1. #1
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    Proof

    Using the general formula for P(A U B U C), prove the following:
    If A, B and C are independent events, then
    P(A) + P(A^c) * P(B) + P(A^c)*P(B^c)*P(C)
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  2. #2
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    Quote Originally Posted by cag31 View Post
    Using the general formula for P(A U B U C), prove the following:
    If A, B and C are independent events, then
    P(A) + P(A^c) * P(B) + P(A^c)*P(B^c)*P(C)
    Prove what? That's an expression- what do you want to prove about it?
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  3. #3
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    Sorry, that P(A U B U C) = P(A) + P(A^C)*P(B)+P(A^c)*P(B^c)*P(C)
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  4. #4
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    Quote Originally Posted by cag31 View Post
    If A, B and C are independent events
    In the expression " A, B and C are independent events" how are you using independence?
    EDIT
    I see your reply to Ivy implies mutual independence.
    Recall that if A~\&~B are independent then so are A^c~\&~B.
    It is simply a matter of set theory: A\cup B\cup C=A\cup (A^c\cap B)\cup (A^c\cap B^c\cap C)
    That is all of A with the part of B left out with the part of C left out of the second term.
    Last edited by Plato; March 8th 2010 at 08:35 AM.
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  5. #5
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    The only information that was received is posted
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