Thread: Proof

Using the general formula for P(A U B U C), prove the following:
If A, B and C are independent events, then
P(A) + P(A^c) * P(B) + P(A^c)*P(B^c)*P(C)

Originally Posted by cag31

Using the general formula for P(A U B U C), prove the following:
If A, B and C are independent events, then
P(A) + P(A^c) * P(B) + P(A^c)*P(B^c)*P(C)

Prove what? That's an expression- what do you want to prove about it?

Sorry, that P(A U B U C) = P(A) + P(A^C)*P(B)+P(A^c)*P(B^c)*P(C)

Originally Posted by cag31

If A, B and C are independent events

In the expression " A, B and C are independent events" how are you using independence?
EDIT
I see your reply to Ivy implies mutual independence.
Recall that if are independent then so are .
It is simply a matter of set theory:
That is all of with the part of left out with the part of left out of the second term.

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