Probability - Normal Distribution

Given that X~N(-3,5^2), calculate the probability.

P(|X|>5)

What I did was transform it and then put calculate the probability with my graphing calculator and got 0.0547992894.

Then, I multiplied it by 2 to get 0.1096.

However, the answer in the book is 0.3994.

Can someone else please do this question and tell me what you get?

Probability - Normal Distribution

I am finding Pr(X > 5) + Pr(X < -5). And I transformed it, so the normal distribution would have a mean of 0 and standard deviation of 1. But the answer is still different from that of the book's.

Probability - Normal Distribution

I know what I did wrong now.

I figured that because I transformed it, then |X|>5 would be symmetrical, but it isn't the case because when I transform it, the two random variables are different. Since I figured it was symmetrical, I multiplied the transformed random variables by 2. But the right way to do it is to add the probabilities of each distinct random variable.