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Math Help - 8 sided die

  1. #1
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    8 sided die

    Hello,
    I have spent a lot of time on this problem, but it just doesn't make anu sense.
    Please any help is highly appreciated....

    If we roll a 8 sided die (0-7) 300 times, by using chebyshev's inequality what's the probability the sample mean is between 3 and 4?
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  2. #2
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    Quote Originally Posted by Johny_Junior View Post
    Hello,
    I have spent a lot of time on this problem, but it just doesn't make anu sense.
    Please any help is highly appreciated....

    If we roll a 8 sided die (0-7) 300 times, by using chebyshev's inequality what's the probability the sample mean is between 3 and 4?
    The mean and standard deviation of a single roll of this die are 3.5 and 2.291..

    The mean and sd of the sample mean are 3.5 and 2.291/sqrt(300)~=0.1323

    Now Chebyshev's inequality tells us that for the sample mean X:

    P(|X-3.5|>= k 0.1323) <= 1/k^2

    Rewording this, we have:

    P((X<=3.5 - k 0.1323) or (X>=3.5 + k 0.1323)) <= 1/k^2

    so if put k 0.1323 = 0.5, we have k=0.5/0.1323~=3.78 then:

    P((X<=3) or (X>=4)) <= 1/3.78^2 ~= 0.07,

    so:

    P(3<X<4) >= 0.93.

    RonL
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