Say I have P(A | B) and I want to find P(A | Bc) where Bc is B complement does that mean P(A | Bc) = 1 - P(A | B)? if not, how would i do it?
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Originally Posted by helpwithassgn P(A | Bc) = 1 - P(A | B)? if not, how would i do it? $\displaystyle P(A|\bar{B})=\frac{P(A\cap\bar{B})}{P(\bar{B})}=\f rac{P(\bar{B})-P(\bar{A}\cap\bar{B})}{P(\bar{B})}=1-P(\bar{A}|\bar{B})$
IF you have independence between A and B then you also have $\displaystyle P(A|\bar B)=P(A)=P(A|B)$
Thanks! Makes sense.
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