1. ## Conditional Probability rule?

Say I have P(A | B)
and I want to find P(A | Bc)
where Bc is B complement

does that mean
P(A | Bc) = 1 - P(A | B)?

if not, how would i do it?

2. Originally Posted by helpwithassgn

P(A | Bc) = 1 - P(A | B)?

if not, how would i do it?
$P(A|\bar{B})=\frac{P(A\cap\bar{B})}{P(\bar{B})}=\f rac{P(\bar{B})-P(\bar{A}\cap\bar{B})}{P(\bar{B})}=1-P(\bar{A}|\bar{B})$

3. IF you have independence between A and B then you also have

$P(A|\bar B)=P(A)=P(A|B)$

4. Thanks!
Makes sense.