Suppose X|Y ~ poisson (mean = y) and Y ~ Uniform [0, 5]
compute Pr [X >= 1]
I think I did it, but need confirmation it's right
E[X] = 2.5
Pr [X >= 1 ] = 1 - e^(-2.5)
this seems overly simple, but is it correct?
Suppose X|Y ~ poisson (mean = y) and Y ~ Uniform [0, 5]
compute Pr [X >= 1]
I think I did it, but need confirmation it's right
E[X] = 2.5
Pr [X >= 1 ] = 1 - e^(-2.5)
this seems overly simple, but is it correct?