Suppose X|Y ~ poisson (mean = y) and Y ~ Uniform [0, 5] compute Pr [X >= 1] I think I did it, but need confirmation it's right E[X] = 2.5 Pr [X >= 1 ] = 1 - e^(-2.5) this seems overly simple, but is it correct?
Last edited by paulrb; Mar 3rd 2010 at 10:25 PM.
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Originally Posted by paulrb Suppose X|Y ~ poisson (mean = y) and Y ~ Uniform [0, 5] compute Pr [X >= 1] I think I did it, but need confirmation it's right E[X] = 2.5 Pr [X >= 1 ] = 1 - e^(-2.5) this seems overly simple, but is it correct? CB
Last edited by CaptainBlack; Mar 5th 2010 at 01:56 AM.
But on 0<y<5 not
Originally Posted by matheagle But on 0<y<5 not Oppss ... working on auto-pilot there. CB
Originally Posted by CaptainBlack CB can this be more simple?
Originally Posted by chialin4 can this be more simple? The last integral is about as simple as you are going to get. CB
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