Can a weighted average be an unbiased estimator of the population mean?

Say we have 3 variables from a sample of known mu: X1, X2, X3

Would the expected value of Z = (1/2)X1 + (1/4)X2 + (1/4)X3 evaluate to mu?

Printable View

- February 16th 2010, 05:59 PMresonanceWeighted Average / Pop Mean
Can a weighted average be an unbiased estimator of the population mean?

Say we have 3 variables from a sample of known mu: X1, X2, X3

Would the expected value of Z = (1/2)X1 + (1/4)X2 + (1/4)X3 evaluate to mu? - February 16th 2010, 06:03 PMmatheagle
yes, as long as .5 +.25+.25 equals one, you have an unbiased estimator.

HOWEVER the variance of this linear combination will be larger than the sample mean's variance.