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Math Help - Hey can someone help? I just can't resolve this problem !

  1. #1
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    Exclamation Hey can someone help? I just can't resolve this problem !

    If X has an exponential distribution with the parameter θ, use the distribution function technique to find the probability density of the random variable Y=ln(x) .

    Thank you for any help !
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  2. #2
    MHF Contributor matheagle's Avatar
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    FIRST of all you need to write down your exponential density.
    There are two ways of writing it, so you need to be clear.
    Then find the cdf and substitute the new rv.

    For example F_Y(y)=P(Y\le y)=P(\ln X\le y)=P(X\le e^y)=F_X(e^y)
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  3. #3
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    What I did until now was
    P(lnx<y)=P(x<e^y)
    and then I was stuck
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  4. #4
    MHF Contributor matheagle's Avatar
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    Quote Originally Posted by pgl1990 View Post
    What I did until now was
    P(lnx<y)=P(x<e^y)
    and then I was stuck
    WRITE down your density of X.
    I need to know how you write YOUR exponential.
    IT makes a diference, one is the reciprocal of the other.
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  5. #5
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    I found exactly the same thing as you in your previous post ( after a few steps)...
    Last edited by pgl1990; February 3rd 2010 at 06:23 AM.
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