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Math Help - Sum of reciprocals

  1. #1
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    Sum of reciprocals

    Hii !

    Can You help me, for this Exercice :

    Prove that for all integer p \geq 3 it exist p of integers natural different two to two n_1 , n_2 , ... , n_p Such as :

    \frac{1}{n_1}+\frac{1}{n_2}+...+\frac{1}{n_p} = 1
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  2. #2
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    Quote Originally Posted by Perelman View Post
    Hii !

    Can You help me, for this Exercice :

    Prove that for all integer p \geq 3 it exist p of integers natural different two to two n_1 , n_2 , ... , n_p Such as :

    \frac{1}{n_1}+\frac{1}{n_2}+...+\frac{1}{n_p} = 1
    Come again?
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  3. #3
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    Wath VonNemo19 ?

    thanks in advance for any help ...
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  4. #4
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    Quote Originally Posted by Perelman View Post
    Hii !

    Can You help me, for this Exercice :

    Prove that for all integer p \geq 3 it exist p of integers natural different two to two n_1 , n_2 , ... , n_p Such as :

    \frac{1}{n_1}+\frac{1}{n_2}+...+\frac{1}{n_p} = 1
    What you have posted makes no sense. Please post the question exactly as it's written from where you got it from.
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  5. #5
    Moo
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    Are you French ???
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  6. #6
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    Quote Originally Posted by Moo View Post
    Are you French ???
    Exactly . by this I have some problemes to traduct ..
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  7. #7
    Moo
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    Oui, j'ai cru voir ça. Pose ta question en Français, je vais (essayer de) traduire
    Sinon, il existe des forums de maths en Français lol, ce qui me paraît être la meilleure solution. Et c'est quoi ton niveau ? Parce que ce ne sont pas des probabilités ça !
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  8. #8
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    Quote Originally Posted by Perelman View Post
    Hii !

    Can You help me, for this Exercice :

    Prove that for all integer p \geq 3 it exist p of integers natural different two to two n_1 , n_2 , ... , n_p Such as :

    \frac{1}{n_1}+\frac{1}{n_2}+...+\frac{1}{n_p} = 1
    This is called "Egyptian fractions" ("fractions égyptiennes"); tu devrais taper ça dans Google, il y a de nombreux sites qui en parlent.
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  9. #9
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    Voiçi, la question en Français :

    prouver que pour tout entier p \geq 3 il existent p d'entiers naturels différents deux à deux n_1 , n_2 , ... , n_p tels que :

    \frac{1}{n_1}+\frac{1}{n_2}+...+\frac{1}{n_p} = 1
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  10. #10
    Moo
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    The question is (for those who're interested ..) :

    Prove that for any integer p \geq 3, there exist p pairwise different positive integers n_1,n_2,\dots,n_p such that :

    <br />
\frac{1}{n_1}+\frac{1}{n_2}+...+\frac{1}{n_p} = 1<br />


    Look at what Laurent referred you to, it should be useful to solve your problem.
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