Sum of reciprocals

**Perelman** · January 29th 2010, 04:47 PM

Hii !

Can You help me, for this Exercice :

Prove that for all integer $p \geq 3$ it exist p of integers natural different two to two $n_1 , n_2 , ... , n_p$ Such as :

$\frac{1}{n_1}+\frac{1}{n_2}+...+\frac{1}{n_p} = 1$

**VonNemo19** · January 29th 2010, 04:55 PM

Originally Posted by Perelman

Hii !

Can You help me, for this Exercice :

Prove that for all integer $p \geq 3$ it exist p of integers natural different two to two $n_1 , n_2 , ... , n_p$ Such as :

$\frac{1}{n_1}+\frac{1}{n_2}+...+\frac{1}{n_p} = 1$

Come again?

**Perelman** · January 29th 2010, 05:08 PM

Wath VonNemo19 ?

thanks in advance for any help ...

**mr fantastic** · January 30th 2010, 01:04 AM

Originally Posted by Perelman

Hii !

Can You help me, for this Exercice :

Prove that for all integer $p \geq 3$ it exist p of integers natural different two to two $n_1 , n_2 , ... , n_p$ Such as :

$\frac{1}{n_1}+\frac{1}{n_2}+...+\frac{1}{n_p} = 1$

What you have posted makes no sense. Please post the question exactly as it's written from where you got it from.

**Moo** · January 30th 2010, 01:38 AM

Are you French ???

**Perelman** · January 30th 2010, 01:53 AM

Originally Posted by Moo

Are you French ???

Exactly . by this I have some problemes to traduct ..

**Moo** · January 30th 2010, 01:56 AM

Oui, j'ai cru voir ça. Pose ta question en Français, je vais (essayer de) traduire

Sinon, il existe des forums de maths en Français lol, ce qui me paraît être la meilleure solution. Et c'est quoi ton niveau ? Parce que ce ne sont pas des probabilités ça !

**Laurent** · January 30th 2010, 02:03 AM

Originally Posted by Perelman

Hii !

Can You help me, for this Exercice :

Prove that for all integer $p \geq 3$ it exist p of integers natural different two to two $n_1 , n_2 , ... , n_p$ Such as :

$\frac{1}{n_1}+\frac{1}{n_2}+...+\frac{1}{n_p} = 1$

This is called "Egyptian fractions" ("fractions égyptiennes"); tu devrais taper ça dans Google, il y a de nombreux sites qui en parlent.

**Perelman** · January 30th 2010, 02:10 AM

Voiçi, la question en Français :

prouver que pour tout entier $p \geq 3$ il existent p d'entiers naturels différents deux à deux $n_1 , n_2 , ... , n_p$ tels que :

$\frac{1}{n_1}+\frac{1}{n_2}+...+\frac{1}{n_p} = 1$

**Moo** · January 30th 2010, 06:59 AM

The question is (for those who're interested ..) :

Prove that for any integer p $\geq 3$ , there exist p pairwise different positive integers $n_1,n_2,\dots,n_p$ such that :

$<br /> \frac{1}{n_1}+\frac{1}{n_2}+...+\frac{1}{n_p} = 1<br />$

Look at what Laurent referred you to, it should be useful to solve your problem.

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