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Math Help - How is the sum of inverse squares distributed?

  1. #1
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    How is the sum of inverse squares distributed?

    if {r_i}, {i=1..N} is normally distributed with equal mean and variance, how is the sum of N inverse squares

    \sum_{i=1}^{N}\frac{1}{{r_i}^2}

    distributed?
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  2. #2
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    Ok, so for r ~ N(0,1) i can model the distribution as the convolution of the inverse chi squared pdfs.

    Now, who can tell me how to do it for non-centrally distributed terms (i.e. \frac{1}{(r-r_0)^2}) ? Is there an expression for a noncentral inverse chi squared distribution?
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