3. Suppose thirty-five percent of adults did not visit their physicians' offices last year. Let x be the number of adults in a random sample of 40 adults who did not visit their physicians' offices last year. For the probability distribution of x:
a] The mean is: _______ because: ______________________
b] The standard deviation is: ________ because: ____________________
NOTE: HINT: use the t statistic to answer problem 4 (you are working with a small sample, n=12)
4.Construct a 99% confidence interval for the mean of the population of all statistics students from which the sample in problem 1 was drawn.
5.According to the American Federation of Teachers, the average salary of 1998 college graduates with a degree in accounting was $33,702 (USA Today, June 18, 1999). Assume that the distribution of current salaries of recent graduates with a degree in accounting is skewed to the right with a mean of $33,702 and a standard deviation of $3,900. Find the probability that the mean current salary of a random sample of 200 recent college graduates with a degree in accounting is within $400 of the population mean.
thank you for any help and suggestion in advance.
You are expected to use the result that a sample mean is approximatly normally distributed with mean equal to the population mean, and sd = population sd/sqrt(N), N the sample size, for large enough samples. (this is the Central Limit Theorem)
So assume the sample mean m~N(33900, (3900^2)/200), so now you need to find the probability p(-400<m-33900<400), or dividing through by 3900/sqrt(N) that:
p(-1.450475<z<1.450475), where z=[m-33900]/[3900/sqrt(200)], has a standard normal distribution.
RonL
1. The test grades for twelve students in a certain statistics class are:
87, 60, 72, 98, 99, 59, 67, 94, 92, 89, 93, 100
a] The mode is Not Available because there are no repetitive pattern within the number set.
b] The mean is 84.167 because this is the calculated result of the mean of this number set.
c] The std. dev. is 15.3435 (show the formula you used)
d] The median is 90.5 because this is the mid range of the number within this set.
e] The range is 41 because this is the highest value and least value gap within the set.
f] The variance is 235.424 because it is the square of the standard deviation.
g] The 35th percentile is _____ because___________________________________________ _
this is the data set for number 4 what information should i use to solve the problem?