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**parallel** we flip a fair coin n times,if k is the number of 'heads' we get,we then flip the coin until we get k+1 heads(the number of flips is not given for the second round),let Y be the number of flips(for the second round)

determine the mean of Y.

here's my logic:

for the first round,this is a bionomial disribution so the mean is:np=n/2

for the second time,we need to get k+1 heads so the mean for the first k heads

is just like before: n/2..and to get the "extra" heads we need to add 2

so the mean is n/2 + 2

now here comes the tricky part..if I add those two i.e n/2 + (n/2 +2 ) = n+2

I get the right answer...but I dunno if it's correct,or why am I allowed to do that.

thanks for your help.