my calculator does not give me a approximate value for b(3.6;4,0.6) !
there is a mistake in the question .I am sorry they are asking for two flaws ,not 1.
- What is the expected number of panels that need to be sampled before two flaws are found.
I guess the steps are the same but for E(x)=2.
In this case is it still a geometric distribution?
Now for problem 2:
the probability is 0.6 that a well driller will find a well of water at a depth less than 100 feet in a certain area. Wells are to be drilled for six new homeowners. Assue that finding a well of water at a depth of less than 100 feet is independent from drilling to drilling and that the probability is 0.6 on every drilling. If X is the number of wells of water found. Find:
My solution: P(X>4)=1-B(4;6,0.6)
Here since mean =3.6, I have problem to find P(X=mean)
Thank you for your time