Okay I need help. I'm studying for a test, and I keep trying to do this problem over and overrr.
This is the table.
Classes ---- Frequency
10-13 ---- 1
14-17 ---- 0
18-21 ---- 15
22-25 ---- 7
26-29 ---- 2
I keep getting 7.93 but my answer sheet says it's supposed to be 3.2!
What am I doing wrong?
I would post my work but I don't know how to .
Thanks in advance!
The question just tells me to find The Standard Deviation of the frequency table posted above. It is to compare standard deviation done by raw data (3.2) and standard deviation done by a grouped data. I know the answer is meant to be 3.2 as well but I don't know how they get this.
Please show the details of your calculation. You might want to read this first and then re-do your calculations: http://www.indiana.edu/~econstat/pdf...pendix%20C.pdf
I get 3.24.
√n[Sigma(f * x^2)] - [Sigma(f*x]^2
_____________________________ = s
n(n-1)
I get
√ [29(11213.9)] - (523.5)^2
______________________
29(28)
So,
325203.1 - 274052.25
___________________
812
51151
_____ = √62.99
812
And then I get 7.93
I got all the results from:
Classes----Frequency ---- Midpoint (x) ---- x^2
10-13 ---- 1 -----11.5------132.25
14-17 ---- 0 -----15.5 ----- 240.25
18-21 ---- 15-----19.5-----380.25
22-25 ---- 7------23.5-----552.25
26-29 ---- 2------27.5-----756.25
And then of course:
x^2*f
132.25
0
5703.75
3865.4
1512.5
Sigma=11213.9
The 523.5 I got from Sigmaf*x
I'm a noob at this. It's my first stats class. And I just realised what you mean. I confused the classes with the n. However, I get 600 when I do n(n-1) and that only makes the standard deviation higher...
Farther from the answer I'm supposed to be getting.
51151
_____= 85.3
600
√85.3 = 9.24
I have given you a link with the formula and which shows how to set things out. It's now nothing more than arithmetic.
Following the link - carefully - I got .
I cannot push the buttons on the calculator for you. And I should not have to be telling you the value of n. It's not a matter of being a 'noob'. It's simply a matter of doing things carefully.