find the margin of error (E) that corresponds to the given statistics and confidence level.

98% confidence; the sample size is 1230, of which 40% are successful.

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- Dec 10th 2009, 01:22 PMsuperman31margin of error
find the margin of error (E) that corresponds to the given statistics and confidence level.

98% confidence; the sample size is 1230, of which 40% are successful. - Dec 11th 2009, 03:18 PMabender
98% confidence level translates to a 2.326348 z score.

MOE = $\displaystyle \sqrt{\frac{(p)(1-p)}{n}} 2.326348 $

Can you finish it from here?

-Andy