(ii) thanks
(iii)
P(X=3,X=6)
= P(Y=6| X=3) * P(X=3)
={ [((3/5)^2) ((2/5)^3) (5C3)]^2 } *[((3/5)^2) ((2/5)^3) (5C3)]
=[((3/5)^2) ((2/5)^3) (5C3)]^3
so,
P(X=3| Y=6)
= P(X=3,X=6)/ P(Y=6)
={[((3/5)^2) ((2/5)^3) (5C3)]^3}/ [((3/5)^4) ((2/5)^6) (10C6)]
=((3/5)^2) ((2/5)^3)((5C3)^3)/ (10C6)
=96/875
AM I RIGHT??