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Math Help - Uniform Variate

  1. #1
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    Uniform Variate

    Question :
    Let X be a Uniform Variate defined on (-k,k). Determine k so that
    P(|X| < 2) = P(|X| > 2)


    Please could please tell me what formula should i use to solve this question?
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  2. #2
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    Quote Originally Posted by zorro View Post
    Question :
    Let X be a Uniform Variate defined on (-k,k). Determine k so that
    P(|X| < 2) = P(|X| > 2)


    Please could please tell me what formula should i use to solve this question?
    What have you tried? Where are you stuck?
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  3. #3
    MHF Contributor matheagle's Avatar
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    use the fact that those are complementary events.
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  4. #4
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    I dont know where to start

    Quote Originally Posted by mr fantastic View Post
    What have you tried? Where are you stuck?

    Mr fantastic i dont know where to start ....No clue at all,,,,If possible coldu please guide me
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  5. #5
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    Quote Originally Posted by zorro View Post
    Mr fantastic i dont know where to start ....No clue at all,,,,If possible coldu please guide me
    Draw a picture and use basic geometry.

    Alternatively:

    \Pr(|X| < 2) = \Pr(|X| > 2)

    \Rightarrow \Pr(|X| < 2) = 1 - \Pr(|X| < 2) (using matheagle's suggestion)

    \Rightarrow \Pr(|X| < 2) = \frac{1}{2}.

    And you really should be able to use either the pdf or simple geometry to calculate \Pr(|X| < 2).

    Hence solve for k.
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  6. #6
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    Quote Originally Posted by mr fantastic View Post
    Draw a picture and use basic geometry.

    Alternatively:

    \Pr(|X| < 2) = \Pr(|X| > 2)

    \Rightarrow \Pr(|X| < 2) = 1 - \Pr(|X| < 2) (using matheagle's suggestion)

    \Rightarrow \Pr(|X| < 2) = \frac{1}{2}.

    And you really should be able to use either the pdf or simple geometry to calculate \Pr(|X| < 2).

    Hence solve for k.


    Mr fantastic could u please tell me how have u put in the value of.................  1- \Pr(|X| < 2) = \frac{1}{2}
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  7. #7
    Grand Panjandrum
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    Quote Originally Posted by zorro View Post
    Mr fantastic i dont know where to start ....No clue at all,,,,If possible coldu please guide me
    I think it is time to ask: Why is it you seem to have no clue where to start with so many of these question? That seems to be the real problem here.

    You have at least some of: notes, a text and Google at your disposal.

    CB
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  8. #8
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    I am sorry for these annoying quetions

    Quote Originally Posted by CaptainBlack View Post
    I think it is time to ask: Why is it you seem to have no clue where to start with so many of these question? That seems to be the real problem here.

    You have at least some of: notes, a text and Google at your disposal.

    CB

    I am sorry for annoying u .....
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  9. #9
    Grand Panjandrum
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    Quote Originally Posted by zorro View Post
    I am sorry for annoying u .....
    You are not annoying me, but it is best to address the real problem which we are not at present.

    Cb
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  10. #10
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    Quote Originally Posted by zorro View Post
    Mr fantastic could u please tell me how have u put in the value of.................  1- \Pr(|X| < 2) = \frac{1}{2}
    Quote Originally Posted by Mr Fantastic

    \Rightarrow \Pr(|X| < 2) = 1 - \Pr(|X| < 2)
    Add \Pr(|X| < 2) to both sides:

    \Rightarrow 2 \Pr(|X| < 2) = 1

    \Rightarrow \Pr(|X| < 2) = \frac{1}{2}

    etc.
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