I am having trouble with this problem I know it might seem really simple but i dont understand how to calculate what the questions ask me.
The probabilty A hits a target is 1/3
The probabilty A hits a target is 1/5
They both fire at the same time.Find the probability of the following:
(i) A does not hit target
(ii) both A and B hit target
(iii) at least one of them hit target
(iv) Neither hit target.
These seem difficult at first but it's really just applying a few concepts on combining probabilities.
Adding A and B for atleast 1 doesn't work, because they are both separate probabilities, unlike dice or a coin.
If you were looking for at least a 1, 2, or 3 on a dice, you would add all 3 probabilities together, so 1/6 + 1/6 + 1/6 = 1/2
However, this is more like the chance of it raining out, if you have a 75% chance that it will rain on days A and B, there's a (25%*25%) 12.5% chance that it won't rain either day, therefore a (1-.125) 87.5% chance that it will rain at least one day.