The monthly starting salaries of students who receive engineering degrees have a standard deviation of $600. What sample size should be selected so that there is 0.95 probability of estimating the mean monthly income within $150 or less
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solve for n in the equation $\displaystyle z_{\alpha/2}\sigma/\sqrt{n}\le B$ with $\displaystyle z_{\alpha/2}=1.96$ B=150 and $\displaystyle \sigma =600$
with B=150 and N = 225 Please let me know if this is correct
the answer is 61. i jsut worked on the formula again
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