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Math Help - Probability Distribution of random variable X.

  1. #1
    Member diddledabble's Avatar
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    Post Probability Distribution of random variable X.

    I need help. I am trying to find the Probability Distribution of random variable X. X is the score of an test. In a multiple choice test of 10 questions with k possible answers (only one is correct). Each correct answers is worth five points. There are no penalties for wrong answers. I know it needs to be the Binomial distribution but what is throwing me off is that the random variable X is the score and not the number of correct answers, even though the two are related. Any idea on how to set this up? I tried P(X=x)= (n choose x) (1/k)^x(1-(1/k)^{(n-x)} but I don't think that accounts for everything.
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  2. #2
    Moo
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    Hello,

    Your formula is correct

    What differs from the score and the number of right answers is that each right answer gives 5 points.
    So the only possible values for x are 0,5,10,15,...,5n
    Note that n=10 here.

    That's all folks !
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  3. #3
    Member diddledabble's Avatar
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    So I need to evaluate for X=0,5,10,15,...,5n but I don't know anything about k except it is greater than or equal to 2. So how do I take that into account? Should it just be a generalized formula for the probability distribution of random variable X?
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  4. #4
    Moo
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    Yes, I think it's a general formula.
    There's no way to know what k is.
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  5. #5
    Member diddledabble's Avatar
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    Moo,
    I still don't think that accounts for everything. You see if x takes on the values 0,5,10...5n then in the formula n choose x you would end up with a (20 choose 50) Having the X be the score seems to make it messier. Our formula if you let x take on the values 0-10 for the number of correct answers would work. But the score messes that up. I was thinking could you do something where P(X=x) is the sum over all possible y's of P(X=x & Y=y)? Where P(Y=y) is our formula with y=0,1,...10.
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