The support of the Poisson distribution can be found here: Poisson distribution - Wikipedia, the free encyclopedia
Here's the question I'm having a little trouble with:
Packets arrive at a Network channel at a mean arrival rate of 72 packets per minute. Assuming that the traffic system is Markovian, find the probability distribution for the number of arrivals in a second.
I am assuming from the above that the mean arrival rate in seconds is 1.2 packets per second
I am also assuming the I have to use:
Poisson Probability Distribution: Prob(x arrivals in a unit time)
λxe-λ
p(x) = -----
x!
Lambda = 1.2 , but what do i need to use for x ( 1 to 60???)
Am i on thr right track with this question??
The support of the Poisson distribution can be found here: Poisson distribution - Wikipedia, the free encyclopedia
My first reply clearly implied agreement that X (the number of packets per second) has a Poisson distribution with a mean of 1.2. It then gave a link to where to get the support for a Poisson distribution.
I have no idea what X=1 is meant to mean (it certainly is not the possble values of X).
I have defined X in post #4. I have agreed with you on the distribution of X. I have told you where to find the possible values of X (the support).
The above collectively defines the probability distribution the question asks you to find. I don't know why you are now calcuating probabilities for different values of X. The posted question does not ask you to do that.