Trying to do this question.
Finding K i get 1/25 but I know this is wrong.
MY method P(1,1) + P(1,3) + P(2,3) = 1
Thanks in advance for your help.
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Trying to do this question.
Finding K i get 1/25 but I know this is wrong.
MY method P(1,1) + P(1,3) + P(2,3) = 1
Thanks in advance for your help.
Hello,
No, you're all correct ! ;)
Note : please next time, put your attachments as .jpg, not .bmp, as it's more painful to open !
Cool thanks! But I thought that P(1,1) = 1/3 and if K= 1/25
Then P(1,1) = 2/25?
Sorry about the pic format I usually change it but forgot this time.
Why would P(1,1)=1/3 ? Because there are only 3 points ?Quote:
Originally Posted by Niall101
This is only correct if we assume that the distribution is uniform.
Which is not necessarily the case.
Yes, P(1,1)=2/25 :)
Cool Thanks so much! Im glad i was on the right track.
Does that same idea hold for when Im getting the marginal function of X
I get 2x^2 / 25 + 10/25 which is getting X over all values of Y where Y can be 1 or 3.
But is it also possible say for x = 1 and y = 50 for example which would still give a value for X even though the joint would give 0?
Perhaps it'll be clearer if you see it written this way :
Letbe the domain of X, namely {1,2}
Letbe the domain of Y, namely {1,3}
Then for any, we have :
Which exactly gives what you got :
if x is inQuote:
2x^2 / 25 + 10/25
If, we still have
, but then these values are 0, according to the definition of P(.,.)
Hey, thanks a lot for your help I appreciate it.(Bow)