Thread: percentile help

F(n(p)) = 2n + 2/n -4
so p = the same

how does 2n + 2/n -4
become 2n^2 -n(4+p) + 2

also
n= .25(4+p+(p^2 + 8)^1/2))

Originally Posted by statman101

F(n(p)) = 2n + 2/n -4
so p = the same

how does 2n + 2/n -4
become 2n^2 -n(4+p) + 2

also
n= .25(4+p+(p^2 + 8)^1/2))

This is incomprehensible to me. Please post the whole question exactly as it's written from wherever you got it from.