F(n(p)) = 2n + 2/n -4 so p = the same how does 2n + 2/n -4 become 2n^2 -n(4+p) + 2 also n= .25(4+p+(p^2 + 8)^1/2))
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Originally Posted by statman101 F(n(p)) = 2n + 2/n -4 so p = the same how does 2n + 2/n -4 become 2n^2 -n(4+p) + 2 also n= .25(4+p+(p^2 + 8)^1/2)) This is incomprehensible to me. Please post the whole question exactly as it's written from wherever you got it from.
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