F(n(p)) = 2n + 2/n -4

so p = the same

how does 2n + 2/n -4

become 2n^2 -n(4+p) + 2

also

n= .25(4+p+(p^2 + 8)^1/2))

Printable View

- November 6th 2009, 01:24 PMstatman101percentile help
F(n(p)) = 2n + 2/n -4

so p = the same

how does 2n + 2/n -4

become 2n^2 -n(4+p) + 2

also

n= .25(4+p+(p^2 + 8)^1/2)) - November 6th 2009, 01:29 PMmr fantastic