P(AUB)=P(A)+P(B)-P(AB)
use indep....
=P(A)+P(B)-P(A)P(B)
=P(A)+P(B)[1-P(A)]
=P(A)+P(B)P(A').
I am stuck in proving that if two events A and B are independent then :
P(AuB)=P(A)+P(A')P(B)
I am stuck with this question i know that if two events are independent then P(AnB)= P(A)P(B)
Can someone please help
thanks