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Math Help - Proof of probability formula involving AuB

  1. #1
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    Proof of probability formula involving AuB

    I am stuck in proving that if two events A and B are independent then :

    P(AuB)=P(A)+P(A')P(B)


    I am stuck with this question i know that if two events are independent then P(AnB)= P(A)P(B)


    Can someone please help

    thanks
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  2. #2
    MHF Contributor matheagle's Avatar
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    P(AUB)=P(A)+P(B)-P(AB)

    use indep....

    =P(A)+P(B)-P(A)P(B)

    =P(A)+P(B)[1-P(A)]

    =P(A)+P(B)P(A').
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  3. #3
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    OK i think i have got the answer

    P(AuB)=P(A)+P(B)-P(A)P(B)
    P(AuB)=P(A)+P(B)(1-P(A)
    P(AuB)=P(A)+P(B)P(A')
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  4. #4
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    ok thank you for your help as i was typing my answer in you had already replied with your answer. Thanks for helping me out though.
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