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Math Help - Finding mean of poisson distribution

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    Finding mean of poisson distribution

    A store opens at 8 in the morning. from 8 until 10 customers arrive at poisson rate 6 per hour. Between 10 and 12 they arrive at a poisson rate of 10 per hour. From 12 to 2, the store closes for lunch, Finally from 2 to 5 the arrival rate drops linearly from 10 per hour at 2 to four per hour at 5. Determin the mean number of customers that enter the store on a given day.

    Firstly Im not sure what to do here except maybe from 2 to 5 we can say the Mean rate is 7 per hour?

    Thanks in advance!
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  2. #2
    MHF Contributor matheagle's Avatar
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    Just add the means per hour.

    (6+6)+(10+10)+(the expected number of vistors from 2 to 5PM)

    I would expect 7 on average on that 3 hours period, (10+4)/2=7

    12 +20 +21=53.

    I think I'm right, but who knows.
    Last edited by matheagle; October 29th 2009 at 04:07 PM.
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    thanks so much. I had this but reckoned it was too easy! Thanks so much for replying I really appreciate it!
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