Math Help Forum: Statistics help.

  1. October 24th, 2009, 07:32 PM #1
    zerolx
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    Statistics help.

    Need help with population mean and margin of error for homework.

    Determine the point estimate of the population mean and margin of error for the Confidence interval.

    Lower bound: 5, upper bound:23

    I would be very grateful and appreciative If someone can help and explain it to me more clearly.
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  3. October 24th, 2009, 09:29 PM #2
    mr fantastic
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    Quote Originally Posted by zerolx View Post
    Need help with population mean and margin of error for homework.

    Determine the point estimate of the population mean and margin of error for the Confidence interval.

    Lower bound: 5, upper bound:23

    I would be very grateful and appreciative If someone can help and explain it to me more clearly.
    More information is required. Please post the question eaxtly as it's written in wherever you got it from.
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  4. October 24th, 2009, 09:43 PM #3
    zerolx
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    Quote Originally Posted by mr fantastic View Post
    More information is required. Please post the question eaxtly as it's written in wherever you got it from.
    That's how it was written in the book. It's # 19

    I'm sorry if images are not allowed.
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  5. October 24th, 2009, 10:08 PM #4
    matheagle
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    The point estimate is the sample mean which is the midpoint of the interval, 14.

    The error, I assume is z_{\alpha/2}s/\sqrt n which is 23-14=9
    Last edited by matheagle; October 24th, 2009 at 10:33 PM.
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  6. October 24th, 2009, 11:54 PM #5
    mr fantastic
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    Quote Originally Posted by matheagle View Post
    The point estimate is the sample mean which is the midpoint of the interval, 14.

    The error, I assume is z_{\alpha/2}s/\sqrt n which is 23-14=9
    Well they say eagles have sharp eyes. Because I just can't see where the values of n, s and \alpha have come from.
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