Can't you just count them?
1-15 - Only One Solution
16-85 - Two Solutions
86-100 - Only One Solution
Thus, 170/10000? -- Assuming that you mean "Absolute Difference". You may not.
Ok i have looked at this problem for at least two hours and cannot come to a conclusion. Can someone please give me a hint or at least tell me my intuition is somewhat sensical.
If two integers between 1 and 100 inclusive are chosen at random, what is the probability that the difference of the two numbers is 15.
So for example i would want to know the probability of getting two arbitrary numbers such as 16 and 1. So therefore each would be 100 choose 1. So (100 choose 1) * (100 choose 1) Would this be correct? Thank you in advance.