What you need to do get E[X] is to evaluate the first derivative of M(t) at t=0.
For the variance, you need to find the second derivative of M(t) and E[X].
I hope that helps.
i got what i got before
1.24
http://www.wolframalpha.com/input/?i=(-e^2+%2B+pi^2)/2
the limit of the derivative of the mgf
as t approaches 0 is that function
and that function is not 1
oh wait, but thats allegedly the mean
i dunno, i don't think its a pdf