An insurer.s annual weather-related loss, X, is a random variable with density function

1. f(x) ={2.5(200)^2:5/x^3.5 for x > 200

0 otherwise

Calculate the difference between the 25th and 75th percentiles of X.

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- Oct 20th 2009, 10:54 AMaffelixPercentiles of a continuous pdf
An insurer.s annual weather-related loss, X, is a random variable with density function

1. f(x) ={2.5(200)^2:5/x^3.5 for x > 200

0 otherwise

Calculate the difference between the 25th and 75th percentiles of X. - Oct 20th 2009, 03:29 PMmr fantastic
Let the 25th percentile be $\displaystyle a$ and the 75th percentile be $\displaystyle b$. Calculate $\displaystyle b - a$ where

$\displaystyle \Pr(X < a) = 0.25$ and $\displaystyle \Pr(X < b) = 0.75$

(it's assumed that you know how to calculate probabilities using a pdf).

If you need more help, please show all you've done and state where you get stuck.