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Math Help - Point me in the right direction please. Probability function

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    Point me in the right direction please. Probability function

    I have done part A but think i am way off. Not even sure what distrubition rules i can follow.

    Edit from my notes I have found this to be a cumulutive prob function.

    Part a
    K= 1 I get 1-.75 = .25

    K=2 1-.25 = .75

    K=3 i get 1- 11/12 = 1/12


    Part b

    P(x < 3/2) U P( X > 1/2)

    = F(3/2)F(1/2)

    Working this out i get 1/2


    Could someone confirm if this is correct please


    Thanks in advance!
    Attached Thumbnails Attached Thumbnails Point me in the right direction please. Probability function-p2.gif  
    Last edited by Niall101; October 18th 2009 at 03:51 PM.
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    Quote Originally Posted by Niall101 View Post
    I have done part A but think i am way off. Not even sure what distrubition rules i can follow.

    Edit from my notes I have found this to be a cumulutive prob function.

    Part a
    K= 1 I get 1-.75 = .25

    K=2 1-.25 = .75

    K=3 i get 1- 11/12 = 1/12


    Part b

    P(x < 3/2) U P( X > 1/2)

    = F(3/2)F(1/2) Mr F says: You mean F(3/2) - F(1/2), right?

    Working this out i get 1/2 Mr F says: Correct.


    Could someone confirm if this is correct please


    Thanks in advance!
    For part (a) Pr(X = 1) = Pr(X = 2) = Pr(X = 3) = 0 because you have a continuous distribution ....
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    Hi thanks for the reply! I still think this is discontinious tho?
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    Quote Originally Posted by Niall101 View Post
    Hi thanks for the reply! I still think this is discontinious tho?
    Yes there are jump discontinuities in the cdf at x = 1, x = 2 and x = 3.
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