Originally Posted by

**nyasha** A baseball player compiles the following information :

He hits a home run in 34% of his games

He gets a strike out in 40% of his games

In 78% of his games he hits a home run or his team wins

In 10% of his games he hits a home run and gets a strike out

In 26% of his games he hits a home run and his team wins

In 28% of his games he gets a strike out and his team wins

In 7% of his games he hits a home run, gets a strike out and his team wins

What is the probability that the players team wins if he doesn't hit a home run ?

Attempt to solution:

$\displaystyle P(W|H')=\frac{P(W \cap H')}{P(H')}=\frac{P(H)-P(W \cap H)}{1-P(H)}$

Guys am l on the right path ? How come l get the wrong answer ?