Thread: Discrete Uniform Random Variable 2

I have the question:

Explain why a discrete uniform random variable, X, on [a,b] has the same variance as a discrete uniform random variable, W, on [1,b-a+1].

Use this information to establish that



...I don't even know where to start so any help would be great cheers

Originally Posted by sirellwood

I have the question:

Explain why a discrete uniform random variable, X, on [a,b] has the same variance as a discrete uniform random variable, W, on [1,b-a+1].

Use this information to establish that



...I don't even know where to start so any help would be great cheers

[a, b] --> [1, b - a + 1] suggests a horizontal translation of -a + 1: W = X - a + 1. And you should know that the shape of a distribution is unaffected by horizontal translation ....

ah ok, so you are saying that Var(X)=(b-a)*(b-a)/12. and Var(W)=(b-a)*(b-a)/12
for the first one a=a, b=b; for the second one a=1, b=b-a+1; so...

Var(X1)=Var(W)?

The b, is a shift and that only changes the mean (center) not the variance (spread).

2b or not 2b? oh well it's 2am.