Consider a signal having probability density function p(f) equals to K exp(-|f|) for -4<f<4 and zero otherwise. Kindly find value of K
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It's an even function, so you don't need two integrals. $\displaystyle .5=k\int_0^4e^{-x}dx=k\bigl(1-e^{-4}\bigr)$
Thanks a lot i think it should be like this 0.5 = K [exp(-4) -1] What u say
Originally Posted by moonnightingale Thanks a lot i think it should be like this 0.5 = K [exp(-4) -1] What u say NOPE 1 look over the chain rule 2 densities must be nonnegative, try calculating your k, with the math you think is correct The derivative and hence integral of $\displaystyle e^{-x} $ is $\displaystyle -e^{-x}$
Last edited by matheagle; Oct 11th 2009 at 11:10 PM.
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