Given the probability distribution:

p (x) = ax^n ,0 ≤ x ≤1, for a positive integer n

What does it mean to normalize p(x) and how would I develop an expression for "a" that normalizes p(x)? Thank you in advance.

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- October 11th 2009, 02:29 PMcarnotnormalizing a probability distribution
Given the probability distribution:

p (x) = ax^n ,0 ≤ x ≤1, for a positive integer n

What does it mean to normalize p(x) and how would I develop an expression for "a" that normalizes p(x)? Thank you in advance. - October 11th 2009, 05:53 PMmr fantastic
- October 11th 2009, 06:32 PMmatheagle
That's a Beta by the way.