What is the equation of the line through the points (3,0) and (6,k)?
note that the point is (3,0 ) and not (0,3)
two point form
(y-y1) / (y2 - y1) =(x-x1) / (x2 - x1)
(y - 0) / (k-0) = (x-3) / (6-3)
simplify and solve for y
y = (k/3) [x-3]
formulae on analytical geometry -----straight lines
No you don't (ignore the given solution), the pdf is a triangle the area under the curve has to be 1 for it to be a pdf, the base is 6, the height k, so the area is 3k=1, so k=1/3.
The given solution has been done by a moron, this question is to test your understanding of pdf's not of algebra and calculus.
CB