Can someone help me with this question...im so lost...thanks in advance... If X has the geometric distribution with parameter p, show that P(X > m + n | X > m) = P(X > n).
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Hello, Well, note that And then just write that because if X>m+n happens, X>m happens too.
Last edited by Moo; October 7th 2009 at 10:39 PM. Reason: thanks
Originally Posted by Moo Hello, Well, note that And then just write that because if X>m+n happens, X>m happens too. I believe you meant to drop that last inequality
Originally Posted by rangergiya Can someone help me with this question...im so lost...thanks in advance... If X has the geometric distribution with parameter p, show that P(X > m + n | X > m) = P(X > n). try the following link for some explanation memoryless property of geometric distribution mean and variance of the geometric distribution
Last edited by qpmathelp; October 8th 2009 at 07:42 AM.
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