Can someone help me with this question...im so lost...thanks in advance...

If X has the geometric distribution with parameter p, show that

P(X > m + n | X > m) = P(X > n).

Printable View

- Oct 5th 2009, 07:41 PMrangergiyaProbability (Geometric Distribution)?
Can someone help me with this question...im so lost...thanks in advance...

If X has the geometric distribution with parameter p, show that

P(X > m + n | X > m) = P(X > n). - Oct 6th 2009, 01:30 PMMoo
Hello,

Well, note that

And then just write that

because if X>m+n happens, X>m happens too. - Oct 7th 2009, 09:48 PMmatheagle
- Oct 8th 2009, 08:30 AMqpmathelp

try the following link for some explanation memoryless property of geometric distribution

mean and variance of the geometric distribution