Results 1 to 2 of 2

Math Help - Conditional Probability Proof

  1. #1
    Newbie
    Joined
    Mar 2009
    Posts
    9

    Conditional Probability Proof

    Can someone help me prove the following?

    For any events A, B, C with P(C) > 0:

    P(A union B | C) = P(A | C) + P(B | C) - P(A intersection B | C)

    Any help is appreciated. Thank you.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor

    Joined
    Aug 2006
    Posts
    18,607
    Thanks
    1574
    Awards
    1
    Quote Originally Posted by tshare1 View Post
    For any events A, B, C with P(C) > 0:
    P(A union B | C) = P(A | C) + P(B | C) - P(A intersection B | C)
    (A\cup B)\cap C=(A\cap C)\cup (B\cap C)
    Therefore P[(A\cup B)\cap C]=P(A\cap C)+P(B\cap C)-P(A\cap B\cap C)
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. conditional probability proof
    Posted in the Advanced Statistics Forum
    Replies: 6
    Last Post: October 15th 2010, 06:21 PM
  2. conditional probability proof...
    Posted in the Advanced Statistics Forum
    Replies: 2
    Last Post: September 23rd 2010, 03:53 PM
  3. Conditional probability proof
    Posted in the Advanced Statistics Forum
    Replies: 2
    Last Post: July 11th 2010, 12:02 PM
  4. conditional probability proof
    Posted in the Advanced Statistics Forum
    Replies: 1
    Last Post: September 8th 2009, 01:52 PM
  5. conditional probability proof
    Posted in the Advanced Statistics Forum
    Replies: 1
    Last Post: September 6th 2008, 02:12 AM

Search Tags


/mathhelpforum @mathhelpforum