Xn+2 = 3Xn+1 - 27/16Xn X0 = 800 X1 = 1000 Xn = ? I've tried iterating it but don't see a pattern...
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Originally Posted by Mitchell Xn+2 = 3Xn+1 - 27/16Xn X0 = 800 X1 = 1000 Xn = ? I've tried iterating it but don't see a pattern... Start by assuming a solution of the form $\displaystyle a \lambda^n$.
Originally Posted by Mitchell Xn+2 = 3Xn+1 - 27/16Xn X0 = 800 X1 = 1000 Xn = ? I've tried iterating it but don't see a pattern... Another suggestion is put in sufficient brackets so we know what you are asking. CB
Captain Black's point is: Is this "Xn+2 = 3Xn+1 - (27/16)Xn" which is relatively simple (and what TheSecondSolution is assuming) or is it "Xn+2 = 3Xn+1 - 27/(16Xn)" which is much harder.
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