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Math Help - Can you help me with springs?

  1. #1
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    Exclamation Can you help me?

    1.Consider a plot of the displacement on the y-axis vs. applied force on the x-axis for an ideal elastic spring. the slope of the curve would be:
    a) the spring constant.
    b) the reciprocal of the spring constant.
    c) the reciprocal of the acceleration of gravity.
    d) the acceleration of gravity.

    2. A 10.0 kg mass hung onto a spring, causes the spring to stretch 2.0 cm the spring constant is.
    a) 49 N/cm
    b) 20.0 N/cm
    c) 5.0 N/cm
    d) 0.020 N/cm
    e) 0.20 N/cm
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  2. #2
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    Quote Originally Posted by LLELLA
    1.Consider a plot of the displacement on the y-axis vs. applied force on the x-axis for an ideal elastic spring. the slope of the curve would be:
    a) the spring constant....

    2. A 10.0 kg mass hung onto a spring, causes the spring to stretch 2.0 cm the spring constant is.
    a) 49 N/cm...
    Hi, LLELLA,

    with a ideal elastic spring the force F and the displacement d are proportional:
    \frac{F}{d}=s\ \mbox{constant value, specific property of the spring}
    From \frac{F}{d}=s\Longrightarrow F(d)=s\cdot d

    The graph of this function is a straight line with the slope s. So it's answer a).

    To 2) I presume that you know that the force equals mass times acceleration. Plug in the values you know and you'll get:
    F=a\cdot m\Longrightarrow F=9.81\frac{m}{s^2}\cdot 10 kg=98.1 N
    Use the formula given above to calculate the spring constant s. Plug in the values you know and solve for s:

    \frac{F}{d}=s\Longrightarrow s=\frac{98.1N}{2 cm}\approx 49\frac{N}{cm}
    So it's answer a again.

    Bye

    EB
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  3. #3
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by earboth
    Hi, LLELLA,

    with a ideal elastic spring the force F and the displacement d are proportional:
    \frac{F}{d}=s\ \mbox{constant value, specific property of the spring}
    From \frac{F}{d}=s\Longrightarrow F(d)=s\cdot d

    The graph of this function is a straight line with the slope s. So it's answer a).

    To 2) I presume that you know that the force equals mass times acceleration. Plug in the values you know and you'll get:
    F=a\cdot m\Longrightarrow F=9.81\frac{m}{s^2}\cdot 10 kg=98.1 N
    Use the formula given above to calculate the spring constant s. Plug in the values you know and solve for s:

    \frac{F}{d}=s\Longrightarrow s=\frac{98.1N}{2 cm}\approx 49\frac{N}{cm}
    So it's answer a again.

    Bye

    EB
    Someone's doing spring constants in units of N/cm? How bizzare!

    -Dan
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