A skydiver jumps off a plane. The only force acting on the skydiver is her weight, inthis free fall. However, when the parachute opens, there is a resistive force ofmagnitude 𝛼𝑣^{2}newtons, where 𝑣 ms-1 is the speed and 𝛼 is a positive constantdepending on the size and construction of the parachute. The skydiver and parachuteare to be modelled throughout as a particle. The total mass of the skydiver and theparachute is 70 kg. Assume the acceleration due to gravity is 10 ms-2.

Consider the parachute is open now. Apply the resistive force to findexpressions for the total distance travelled by the skydiver in terms of t and 𝛼.

I am only able to figure out ma = mg - 𝛼𝑣^{2 }

I've tried integrating 3 different equations to get the total displacement but on second thoughts i think it is wrong as t will not hold true for all 3 equations. I will greatly appreciate some help so i can continue from there and try to figure out the answer. Thanks in advance..