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Thread: Newtonian Mechanics

  1. #1
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    Newtonian Mechanics

    A block of mass m is given an initial velocity of u0 at a fixed origin O and it began toslide on a rough horizontal surface. At a position x from O, it has a velocity of v. Takethe magnitude of the acceleration due to gravity to be g and the coefficient of slidingfriction to be μ. (a) Apply Newtonian mechanics and present the equation of motion for the block. the answer i got was a=μg. anyone out there could confirm if i am right? or help me if i am wrong
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  2. #2
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    Re: Newtonian Mechanics

    $|a| = \mu g$ ... you've stated the magnitude of acceleration.

    kinetic friction acts opposite to the direction of motion ...

    $a= \dfrac{F_{net}}{m} = \dfrac{-\mu mg}{m} = -\mu g$

    $v = u_0 - \mu g t$


    also, the work/kinetic energy theorem yields an equation of motion without the parameter of time ...

    $W_{net} = -f \cdot x = \Delta KE = \dfrac{1}{2}mv^2 - \dfrac{1}{2}m u_0^2$

    $-\mu mg x = \dfrac{1}{2}m(v^2-u_0^2)$

    $v^2 = u_0^2 - 2\mu g x$
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    Re: Newtonian Mechanics

    i see. thanks for the clarification
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