Let z=3(cos(-1/3*pi)+i sin(-1/3*pi))
What is the modulus of z^3
|z^3| =
I'm not quite sure how to go about this can anyone help please ,I struggle with powers of complex numbers .
Thanks
ahh right ,I'd have to find R first right ?
I know on the cartesian plane its |z| = sqrt *a^2+b^2 ...how about in polar form how would I find R ....not sure if my answers right or not ,Thanks
ahh right ,I'd have to find R first right ?
I know on the cartesian plane its |z| = sqrt *a^2+b^2 ...how about in polar form how would I find R ....not sure if my answers right or not ,Thanks
You've been given the complex number in polar form , ie r(cos(A) + i sin(A)) so r = 3